Question

6pbo(s)+o2(g) 2pb3o4(s)

Answer 1

Answer on Question #42795, Chemistry, Other

Question:

6pbo(s)+o2(g) 2pb3o4(s)

Answer:

Lead(II,IV) oxide (Pb₃O₄), also called minium, red lead or triplumbic tetroxide, is a bright red or orange crystalline or amorphous pigment. Chemically, red lead is Pb₃O₄, or 2 PbO·PbO₂. Lead(II,IV) oxide is used in the manufacture of batteries, lead glass and rust-proof primer paints.

Lead(II,IV) oxide is prepared by calcination of lead(II) oxide (also called litharge) in air at about 450 to 480 °C:

$$6 \mathrm{PbO}(s) + \mathrm{O}_2(g) \rightarrow 2 \mathrm{Pb}_3\mathrm{O}_4(s)$$

The resulting material is contaminated with lead(II) oxide (PbO). If a pure compound is desired, PbO can be removed by a potassium hydroxide solution:

$$\mathrm{PbO} + \mathrm{KOH} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{K}[\mathrm{Pb(OH)}_3] \text{ (aq)}$$

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