Question

the total number of valence electron in 4.2g of N3 ion is?

Answer 1

Answer on Question #42543, Chemistry, Other

Question:

the total number of valence electron in 4.2g of N3 ion is?

Solution:

Electronic configuration N³⁻ ion = 1s² 2s² 2p⁶

Atomic mass of N = 14 g/mole

Therefore, number of moles of nitride ions in 4.2 g = 4.2/14 = 0.3 moles

Therefore, number of nitride ions in 0.3 moles = 0.3 x 6.022 x 10²³

Number of valence electrons in one nitride ion = 8

So, number of valence electrons in 0.3 x 6.022 x 10²³ nitride ions = 8 x 0.3 x 6.022 x 10²³

= 14.45 x 10²³ = 1.445 x 10²⁴

Answer: 1.445 x 10²⁴.

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