Question

a quantity of chlorine gas occupies a volume of 50L at 27c and 721kPa. how many gram of chlorine gas are present

Answer 1

Answer on Question #42379 - Chemistry - Other

Question:

A quantity of chlorine gas occupies a volume of 50L at 27c and 721kPa. How many gram of chlorine gas are present?

Answer:

The ideal gas law is:

$$PV = nRT$$

where $P$ is the absolute pressure of the gas, $V$ is the volume of the gas, $n$ is the amount of substance of gas (measured in moles), $R$ is the ideal, or universal, gas constant, and $T$ is the absolute temperature of the gas.

Absolute pressure of chlorine gas equals:

$$P = 721\,kPa = 721000\,Pa$$

Volume of chlorine gas equals:

$$V = 50\,L = 5 \cdot 10^{-2}\,m^3$$

Absolute temperature of chlorine gas is:

T = 27\,^{\circ}\mathrm{C} = 300\,K

That's why the number of moles of chlorine gas is:

$$n = \frac{PV}{RT} = \frac{721000 \cdot 5 \cdot 10^{-2}}{8.314 \cdot 300} = 14.45\,mol$$

Mass of chlorine gas equals:

$$m = n \cdot M$$

where $M$ is the molar mass of chlorine gas, $M = 71\,g/mol$.

So the mass of 14.45 mol of chlorine gas equals:

$$m = 14.45 \cdot 71 = 1025.95\,g$$

Answer: $m(\mathrm{Cl}_2) = 1025.95\,g$

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