Question

How many moles of nitrogen gas are in 78.4L at STP?

Answer 1

Answer on Question #42185 - Chemistry - Other

Question:

How many moles of nitrogen gas are in 78.4L at STP?

Solution:

At STP one mole of a gas occupies volume of 22.4L, which is called molar volume $(V_{m})$. Thus, number of moles of a gas $(n)$ in given volume $(V)$ equals

$$n = \frac{V}{V_{m}} = \frac{78.4L}{22.4L/mol} = 3.5 \text{ moles}$$

Answer: 3.5 moles

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