Question

What is the mass of sodium nitrate (85.00 g/mol) that releases 2.55 L of Oxygen has at STP

Answer 1

Answer on Question #42142, Chemistry, Other

Question:

What is the mass of sodium nitrate (85.00 g/mol) that releases 2.55 L of Oxygen has at STP

Solution:

Sodium nitrate decomposes via thermal decomposition at $380^{\circ}\mathrm{C}$ to sodium nitrite:

$$2NaNO_3 = 2NaNO_2 + O_2$$

Amount of substance of 2.55 L of Oxygen at STP is:

$$\mathrm{N(O_2) (mole)} = 2.55 / 22.711 = 0.1123;$$

Now we can find the mass of sodium nitrate:

$$\mathrm{M(NaNO_3) (g)} = 0.1123 * 2 * 85.00 = 19.09;$$

Answer: 19.09 g

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