Question

N2O4(aq)<-->2NO2(g)
Keq=11
you start with IM N2O4 and then the system goes to equilibrium. Find the equilibrium concentrations of each material.

Answer 1

Answer on Question #41969, Chemistry, Other

Question:

N2O4(aq) <--> 2NO2(g)

Keq=11

you start with IM N2O4 and then the system goes to equilibrium. Find the equilibrium concentrations of each material.

Answer:

$$\mathrm{N_2O_4(aq)} \ <--> \ 2\mathrm{NO_2(g)}$$

Starting concentrations (mole/L): 1 0

Equilibrium concentrations (mole/L): 1-x 2x

$$\mathrm{K_{eq}} = [\mathrm{NO_2}]^2 / [\mathrm{N_2O_4}]$$ $$11 = (2x)^2 / 1 - x$$ $$11 = 4x^2 / 1 - x$$ $$4x^2 = 11 - 11x$$ $$4x^2 + 11x - 11 = 0$$ $$x = 0.78$$

The equilibrium concentrations of $\mathrm{N_2O_4}$ will be: $1 - 0.78 = 0.22$ mole/L

The equilibrium concentrations of $\mathrm{NO_2}$ will be: $2*0.78 = 1.56$ mole/L

Answer:

0.22 and 1.56 mole/L of $\mathrm{N_2O_4}$ and $\mathrm{NO_2}$ respectively.

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