Question

Mixture of 100 ml 0.1 M H3PO4 and 100 ml 0.1 M NaOH will be

Answer 1

Answer on Question #41128, Chemistry, Other

Question:

Mixture of 100 ml 0.1 M H₃PO₄ and 100 ml 0.1 M NaOH will be

Solution:

Components of mixture react:

$$H_3PO_4 + NaOH = NaH_2PO_4 + H_2O$$

Amount of substance of resulting salt will be:

$$N(NaH_2PO_4)(mol) = N(NaOH) = 0.1 \times 0.1 = 0.01;$$

Next we must found the volume of resulting solution. It consists of volume of both solutions and volume of yield water:

$$V(\text{Resulting solution})(l) = V(H_3PO_4) + V(NaOH) + V(H_2O) = 0.1 + 0.1 + 0.01 \times 18 \times 0.001 = 0.20018;$$

Molarity of the resulting solution will be:

$$M(NaH_2PO_4)(mol/l) = 0.01 / 0.20018 = 0.05$$

Answer: 200.18 ml of 0.05 M NaH₂PO₄

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