Answer to Question #41036 in Chemistry for Jordynn

Question #41036

X2 + 3Y2 --> 2XY3 triangle H1= -320 kJ
X2 + 2Z2 --> 2xZ2 triangle H2= -170 kJ
2Y2 + Z2 --> 2Y2Z triangle H3= -250 kJ
Calculate the change in enthalpy for the following reaction:
4XY3 + 7Z2 --> 6Y2Z + 4XZ2
Triangle H =____?___ kJ

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