Answer on Question #40472 – Chemistry – Other
For the following chemical reaction, what mass of calcium carbonate (in grams) will be produced from 5.03 mol of sodium carbonate?
Na2CO3 + Ca(NO3)2 ---> CaCO3 + 2NaNO3
Answer:
From reaction we see n (Na2CO3) = n (CaCO3).
So, as result of this reaction 5.03 mol of CaCO3 is produced.
The next step is finding of mass of CaCO3: m (CaCO3) = n (CaCO3) * M (CaCO3) = 5.03 * 100 = 503gr.