Question

Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide:

2NaI(aq) + Cl2(g) ---> I2(s) + 2NaCl(aq)

How many grams of sodium iodide, NaI, must be used to produce 40.4 g of iodine, I2?

Answer 1

Answer on Question #40470 – Chemistry – Other

Iodine is prepared both in the laboratory and commercially by adding Cl₂(g) to an aqueous solution containing sodium iodide:

$$2 \mathrm {N a l} (\mathrm {a q}) + \mathrm {C l} 2 (\mathrm {g}) - - - \& \mathrm {g t}; \mathrm {I} 2 (\mathrm {s}) + 2 \mathrm {N a C l} (\mathrm {a q})$$

How many grams of sodium iodide, NaI, must be used to produce 40.4 g of iodine, I2?

Solution

x g 40.4 g

$$2 \mathrm {N a l} (\mathrm {a q}) + \mathrm {C l} _ {2} (\mathrm {g}) \rightarrow \mathrm {I} _ {2} (\mathrm {s}) + 2 \mathrm {N a C l} (\mathrm {a q})$$

300 g 254 g

$$X = 40.4 \mathrm{g} \cdot 300 \mathrm{g} / 254 \mathrm{g} = 47.7 \mathrm{g}$$

Answer: 47.7 g of sodium iodide