Question

When heated, KClO3 decomposes into KCl and O2.
2KClO3 ---> 2KCl +302
If this reaction produced 74.6 g of KCl, how much O2 was produced (in grams)?

Answer 1

Answer on Question#40463-Chemistry-Other

Question

When heated, KClO₃ decomposes into KCl and O₂.

$$2 \mathrm{KClO_3} \rightarrow 2 \mathrm{KCl} + 3 \mathrm{O_2}$$

If this reaction produced 74.6 g of KCl, how much O₂ was produced (in grams)?

Solution

Based on the chemical equation and molar mass values (M_KCl = 74.6 g/mol, M_O₂ = 32.0 g/mol) we may write the proportion:

$$2 \mathrm{mol} \cdot 74.6 \mathrm{g/mol} (\mathrm{KCl}) - 3 \mathrm{mol} \cdot 32.0 \mathrm{g/mol} (\mathrm{O_2})$$ $$74.6 \mathrm{g} (\mathrm{KCl}) - X \mathrm{g} (\mathrm{O_2})$$ $$X = 3 \cdot 32.0 \cdot 74.6 / 2 \cdot 74.6 = 48.0 \mathrm{g}$$

Answer: 48.0 g of O₂ was produced.