Question #40108

How do you prepare 50.0 ml of .03 M concentrated hydrochloric acid.calculate the amount needed,the dilution scheme and actual final concentration?

Expert's answer

Answer on Question#40108 - Chemistry - Other

How do you prepare 50.0 ml of .03 M concentrated hydrochloric acid? calculate the amount needed, the dilution scheme and actual final concentration?

**Solution.**

The amount of HCl:


C1V1=C2V2\mathrm{C_1V_1 = C_2V_2}


We need to find the volume of 1 M HCl, which will be dilute.


V2=C1V1C2V_2 = \frac{C_1V_1}{C_2}V2=0.03M×0.05L/1M=0.0015LV_2 = 0.03 \, \text{M} \times 0.05 \, \text{L} / 1 \, \text{M} = 0.0015 \, \text{L}


So, we take 1.5 mL of 1 M solution HCl and diluted to 50 mL. Concentration of the solution will be 0.03 M

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