Question

How many milliliters of 0.121 M H2SO4 are needed to neutralize 0.150g of NaOH?

Answer 1

Answer on Question#39838, Chemistry, Other

Question:

How many milliliters of 0.121 M H₂SO₄ are needed to neutralize 0.150g of NaOH?

Answer:

An equation of the reaction is:

$$2 \mathrm{NaOH} + \mathrm{H_2SO_4} = \mathrm{Na_2SO_4} + 2 \mathrm{H_2O}$$

Moles of NaOH = 0.150/40 = 0.00375 moles.

The mole ratio of this equation is:

$$n(\mathrm{NaOH}) / n(\mathrm{H_2SO_4}) = \frac{2}{1}$$

The moles of H₂SO₄ = 0.00375/2 = 0.001875 moles

The volume of H₂SO₄ we can be found from formula:

$$C = \frac{n}{V}$$ $$V = \frac{0.0011875}{0.121} = 0.0155L = 15.5 \mathrm{ml}$$