Question #39578

How many nitrogen atoms are there in 2.954 g of ammonia?

Expert's answer

Answer on Question#39578 - Chemistry - Other

Question:

How many nitrogen atoms are there in 2.954 g of ammonia?

Solution

M(NH₃) = 17 g/mol

n(NH₃) = 2.954/17 = 0.174 mol

N = Nₐ·n, Nₐ = 6,02·10²³ mol⁻¹

N = (6,02·10²³ 1/mol)·0,174 mol = 1.05·10²³

Answer: N = 1.05·10²³

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