Answer on Question#39578 - Chemistry - Other
Question:
How many nitrogen atoms are there in 2.954 g of ammonia?
Solution
M(NH₃) = 17 g/mol
n(NH₃) = 2.954/17 = 0.174 mol
N = Nₐ·n, Nₐ = 6,02·10²³ mol⁻¹
N = (6,02·10²³ 1/mol)·0,174 mol = 1.05·10²³
Answer: N = 1.05·10²³