Question

how to balance MnS+HCl+HNO3 --> MnCl2+NO+S+H2O

Answer 1

Answer on Question#39261 - Chemistry - Inorganic Chemistry

Question:

How to balance MnS+HCl+HNO₃ → MnCl₂+NO+S+H₂O

Answer:

Write the electron balance for this equation:

$$\begin{array}{l} S-2 - 2e- \rightarrow S0 \quad | 2 | 3 \\ N+5 + 3e- \rightarrow N+2 \quad | 3 | 2 \\ \end{array}$$

Hence the coefficients near sulfur-containing substance is 3, and the one near nitrogen compounds is 2:

$$3 \mathrm{MnS} + ? \mathrm{HCl} + 2 \mathrm{HNO}_3 \rightarrow 3 \mathrm{MnCl}_2 + 2 \mathrm{NO} + 3 \mathrm{S} + ? \mathrm{H}_2\mathrm{O}$$

Now we can find the coefficients near $\mathrm{H}_2\mathrm{O}$ and HCl via oxygen and hydrogen balance. Then check the correctness via chlorine balance.

$$3 \mathrm{MnS} + 6 \mathrm{HCl} + 2 \mathrm{HNO}_3 \rightarrow 3 \mathrm{MnCl}_2 + 2 \mathrm{NO} + 3 \mathrm{S} + 4 \mathrm{H}_2\mathrm{O}$$