Question

How would you prepare a solution S of pottasium iodide with a mass concentratiin of 8.4g.l-1 in v=250ml? What is the molar concentration C of the solution?

Answer 1

How would you prepare a solution S of potassium iodide with a mass concentration of 8.4 g.l-1 in v=250ml? What is the molar concentration C of the solution?

Solution:

$$\mathrm{m(KJ)(g)} = \frac{8.4 \times 250}{1000} = 2.1$$ $$C = \frac{n}{V} = \frac{m}{MV}$$ $$C(\text{mole/l}) = \frac{2.1}{166 \times 0.25} = 0.0506$$

Answer: 2.1 g of KJ; C = 0.0506 M