What the volume of 88 grams of carbon dioxide?
Solution:
At Standard temperature and pressure (STP), volume of one mol of any gas is 22.4 L.
Molecular mass of carbon dioxide is:
ma(CO2)=ma(C)+2×ma(O)ma(CO2)(g/mole)=12+2×16=44
Volume of 88 grams of carbon dioxide at STP is
22.4×88/44=44.8L
Answer: 44.8 L.