Question #350675

6. Nitrous oxide, NO, is sometimes used in dentistry. It is produced when

ammonium nitrate(NH,NOg) decomposes in the reaction below.

(NHANO3) - N20 + 2H20

a. How many moles of NH,NO; are required to produce 5.6 moles of Ng0?

b. How many grams of NO is that?

Expert's answer

**Solution:**

Balanced chemical equation:

NH_{4}NO_{3} → N_{2}O + 2H_{2}O

According to stoichiometry:

1 mol of NH_{4}NO_{3} is required to produce 1 mol of N_{2}O

**X** mol of NH_{4}NO_{3} is required to produce 5.6 mol of N_{2}O

Thus,

Moles of NH_{4}NO_{3} = **X** = (5.6 mol N_{2}O) × (1 mol NH_{4}NO_{3} / 1 mol N_{2}O) = 5.6 mol NH_{4}NO_{3}

Therefore, **5.6 moles of NH**_{4}**NO**_{3}** are required to produce 5.6 moles of N**_{2}**O**

The molar mass of N_{2}O is 44 g/mol

Therefore,

Mass of N_{2}O = (5.6 mol N_{2}O) × (44 g N_{2}O / 1 mol N_{2}O) = 246.4 g

**That is 246.4 grams of N**_{2}**O**

**Answer: **

**5.6 moles of NH**_{4}**NO**_{3}** are required to produce 5.6 moles of N**_{2}**O;**

**that is 246.4 grams of N**_{2}**O**

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