Answer to Question #349098 in Chemistry for tuba

Question

What is the percentage composition of Na2SO4?

Answer 1

Solution:

M_r(Na₂SO₄) = 2×A_r(Na) + A_r(S) + 4×A_r(O) = 2×22.99 + 32.065 + 4×15.999 = 142.041

%Na in Na₂SO₄ = [2×A_r(Na) / M_r(Na₂SO₄)] × 100%

%Na in Na₂SO₄ = [2×22.99 / 142.041] × 100% = 32.37%

%Na in Na₂SO₄ = 32.37%

%S in Na₂SO₄ = [A_r(S) / M_r(Na₂SO₄)] × 100%

%S in Na₂SO₄ = [32.065 / 142.041] × 100% = 22.57%

%S in Na₂SO₄ = 22.57%

%O in Na₂SO₄ = [4×A_r(O) / M_r(Na₂SO₄)] × 100%

%O in Na₂SO₄ = [4×15.999 / 142.041] × 100% = 45.06%

%O in Na₂SO₄ = 45.06%

The percentage composition of sodium sulfate (Na₂SO₄) is 32.37% sodium (Na), 22.57% sulfur (S), and 45.06% oxygen (O)