Answer to Question #347822 in Chemistry for Pampam

Question #347822

Identify oxidizing agent and reducing agent in the reactions.


1. 2Na2S2O3 + I2 → Na2S4O6+ 2Nal


2. N2+ 3H2 → 2NH3


3. 2FeCl3 + H2S → 2FeCl2 +S + 2HC1


4. 2 Cr3 + H2O+ 6CIO3 → Cr2O72 + 6CIO2 + 2H+


5. 3Mg + N₂ → Mg3N2

1
Expert's answer
2022-06-06T03:38:08-0400

Solution:

(1): 2Na2S2O+ I2 → Na2S4O6 + 2Nal

Oxidation half-reaction:

2S2O32− − 2e → S4O62−

Reduction half-reaction:

I20 + 2e− → 2I

Therefore,

Na2S2O3 acts as reducing agent

I2 acts as oxidizing agent


(2): N2 + 3H2 → 2NH3

Oxidation half-reaction:

H2− 2e → 2H+

Reduction half-reaction:

N20 + 6e− → 2N−3

Therefore,

H2 acts as reducing agent

N2 acts as oxidizing agent


(3): 2FeCl3 + H2S → 2FeCl2 + S + 2HCl

Oxidation half-reaction:

S2− − 2e → S0

Reduction half-reaction:

Fe3+ + e− → Fe2+

Therefore,

H2S acts as reducing agent

FeCl3 acts as oxidizing agent


(4): Cr3+ + H2O + 6CIO3 → Cr2O72− + 6CIO+ 2H+

Oxidation half-reaction:

2Cr3+ + 7H2O − 6e → Cr2O72− + 14H+

Reduction half-reaction:

CIO3 + 2H+ + e− → CIO2 + H2O

Therefore,

Cr3+ acts as reducing agent

CIO3 acts as oxidizing agent


(5): 3Mg + N2 → Mg3N2

Oxidation half-reaction:

Mg0 − 2e → Mg2+

Reduction half-reaction:

N20 + 6e− → 2N−3

Therefore,

Mg acts as reducing agent

N2 acts as oxidizing agent

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