Solution:
Balanced chemical equation:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
According to stoichiometry:
Moles of H2SO4 = Moles of NaOH / 2
or:
2 × Molarity of H2SO4 × Volume of H2SO4 = Moles of NaOH
Therefore,
Molarity of H2SO4 = (Moles of NaOH) / (2 × Volume of H2SO4)
Molarity of H2SO4 = (0.0400 mol) / (2 × 0.0100 L) = 2.00 mol/L = 2.00 M
The molarity of H2SO4 solution is 2.00 M
Answer: The [H2SO4] is 2.00 M
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