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Answer to Question #34706 in Chemistry for james
Question #34706
A solution contains 50g/dm3 of impure sodium hydroxide. 25cm3 of it got neutralised by 14cm3 of sulfuric acid. Sulfuric acid = 1mol/dm3
H2SO4+2NaOH = Na2SO4+2H2O
-No. Of moles of sulfuric acid present in 14cm3 of the solution.
-Concentration of sodium hydroxide
-Percentage purity of sodium hydroxide.
H2SO4+2NaOH = Na2SO4+2H2O
-No. Of moles of sulfuric acid present in 14cm3 of the solution.
-Concentration of sodium hydroxide
-Percentage purity of sodium hydroxide.
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