What is the PH of a solution whose hydroxide
-3
ion (OH) is 0.003 moldm
Solution:
[OH−] = 0.003 mol dm−3 = 0.003 M
We can convert between [OH−] and pOH using the following equation:
pOH = −log[OH−] = −log(0.003) = 2.52
For any aqueous solution at 25∘C:
pH + pOH = 14
pH = 14 − pOH = 14 − 2.52 = 11.48
pH = 11.48
Answer: pH = 11.48
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