Answer to Question #344916 in Chemistry for Donnie

Question

How many moles of ethanol is produced if you start with 8.74 g of glucose

Answer 1

Solution:

ethanol = C₂H₅OH

glucose = C₆H₁₂O₆

The molar mass of glucose is 180.156 g/mol

Therefore,

Moles of C₆H₁₂O₆ = (8.74 g C₆H₁₂O₆) × (1 mol C₆H₁₂O₆ / 180.156 g C₆H₁₂O₆) = 0.0485 mol C₆H₁₂O₆

Balanced chemical equation for the fermentation of glucose to ethanol:

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

According to stoichiometry:

1 mol of C₆H₁₂O₆ produces 2 mol of C₂H₅OH

Thus, 0.0485 mol of C₆H₁₂O₆ produce:

(0.0485 mol C₆H₁₂O₆) × (2 mol C₂H₅OH / 1 mol C₆H₁₂O₆) = 0.097 mol C₂H₅OH

Answer: 0.097 moles of ethanol (C₂H₅OH) is produced