Oxygen gas inside a 1.5 L gas tank has a pressure of 0.95 atm. Provide the temperature remains constant, how much pressure is needed to reduce it's volume by 1/2
Given:
P1 = 0.95 atm
V1 = 1.5 L
T1 = T2 = constant
P2 = unknown
V2 = (1/2) × V1 = (1/2) × 1.5 L = 0.75 L
Formula: P1V1 = P2V2
Solution:
Since the temperature and amount of gas remain unchanged, Boyle's law can be used.
Boyle's gas law can be expressed as: P1V1 = P2V2
To find the pressure, solve the equation for P2:
P2 = P1V1 / V2
P2 = (0.95 atm × 1.5 L) / (0.75 L) = 1.90 atm
P2 = 1.90 atm
Answer: 1.90 atm
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