Answer to Question #342707 in Chemistry for Raul Ayala

Question

a 10.0L cylinder of gas is stored at room temperature (20.0c) and a pressure of 1800psi if the gas is transferred to a 6.0L cylinder at what temperature would it have to be stored in order for the pressure to remain at 1800 psi

Answer 1

Given:

V₁ = 10.0 L

T₁ = 20.0°C + 273 = 293 K

P₁ = P₂ = 1800 psi = constant

V₂ = 6.0 L

T₂ = unknown

Formula: V₁/T₁ = V₂/T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the resulting temperature, solve the equation for T₂:

T₂ = V₂T₁ / V₁

T₂ = (6.0 L × 293 K) / (10.0 L) = 175.8 K = 176 K

T₂ = 176 K (or −97.0°C)

Answer: at −97.0°C