if p1=4 atm and v1=3 l, what will v2 be if p2=7.3 atm?
Given:
P1 = 4 atm
V1 = 3 L
T = constant
P2 = 7.3 atm
V2 = unknown
Formula: P1V1 = P2V2
Solution:
Since the temperature and amount of gas remain unchanged, Boyle's law can be used.
Boyle's gas law can be expressed as: P1V1 = P2V2
To find the volume, solve the equation for V2:
V2 = P1V1 / P2
V2 = (4 atm × 3 L) / (7.3 atm) = 1.6438 L = 1.64 L
V2 = 1.64 L
Answer: V2 = 1.64 L
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