Question

3.At 25⁰C, the volume of chlorine gas is 15 dm³ .What is the resulting volume if the temperature is adjusted to 320K provided that the pressure remains constant?

Answer 1

Given:

V₁ = 15 dm³

T₁ = 25°C + 273 = 298 K

P₁ = P₂ = constant

V₂ = unknown

T₂ = 320 K

Formula: V₁/T₁ = V₂/T₂

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the resulting volume of chlorine gas, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (15 dm³ × 320 K) / (298 K) = 16.11 dm³

V₂ = 16.11 dm³

Answer: The resulting volume of chlorine gas is 16.11 dm³