3.At 250C, the volume of chlorine gas is 15 dm3 .What is the resulting volume if the temperature is adjusted to 320K provided that the pressure remains constant?
Given:
V1 = 15 dm3
T1 = 25°C + 273 = 298 K
P1 = P2 = constant
V2 = unknown
T2 = 320 K
Formula: V1/T1 = V2/T2
Solution:
Since the pressure and amount of gas remain unchanged, Charles's law can be used.
Charles's law can be expressed as: V1 / T1 = V2 / T2
V1T2 = V2T1
To find the resulting volume of chlorine gas, solve the equation for V2:
V2 = V1T2 / T1
V2 = (15 dm3 × 320 K) / (298 K) = 16.11 dm3
V2 = 16.11 dm3
Answer: The resulting volume of chlorine gas is 16.11 dm3
Comments
Leave a comment