Answer to Question #340006 in Chemistry for belen

Question

A 10.0 mL sample of H₂SO₄ was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the normality of the H₂SO₄?

Answer 1

Solution:

Balanced chemical equation:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

According to stoichiometry:

Normality of H₂SO₄ × Volume of H₂SO₄ = Normality of KOH × Volume of KOH

Normality of KOH = Molarity of KOH = 1.0 M

Therefore,

Normality of H₂SO₄ = (Normality of KOH × Volume of KOH) / (Volume of H₂SO₄)

Normality of H₂SO₄ = (1.0 N × 13.5 mL) / (10.0 mL) = 1.35 N

Normality of H₂SO₄ = 1.35 N

Answer: The normality of the H₂SO₄ solution is 1.35 N