Question #339605
calculate the heat required to boil 325 g of water
Expert's answer
Q=C x m x deltaT
C=4.18 kJ / (kg x K)
Q= 4.18 x 0.325 x (100-0)=135.85 kJ
calculate the heat required to boil 325 g of water
Q=C x m x deltaT
C=4.18 kJ / (kg x K)
Q= 4.18 x 0.325 x (100-0)=135.85 kJ
