Question #33758

Adjust the density formula and solve the problems below:
Adjust the formula for the unknown m =

The density of silver is 110.49 g/cm3. If a sample of pure silver has a volume of 112.993 cm3, what would the mass?

Expert's answer

Question #33758

Adjust the density formula and solve the problems below:

Adjust the formula for the unknown m=m =

The density of silver is 110.49 g/cm3110.49\ \mathrm{g/cm^3}. If a sample of pure silver has a

volume of 112.993 cm3112.993\ \mathrm{cm^3}, what would the mass?

Solution:

According to density formula, d=mVd = \frac{m}{V}, so m=dV=112.993×110.49=12484.597 g=12.484 kgm = d \cdot V = 112.993 \times 110.49 = 12484.597\ \mathrm{g} = 12.484\ \mathrm{kg}

**Answer:** The mass would be 12.484 kg12.484\ \mathrm{kg}.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS