An aqueous solution of sodium bromide, NaBr, contains 3.40 grams of sodium bromide and 17.4 grams of water.
The percentage by mass of sodium bromide in the solution is %.
Solution:
Mass of solute = Mass of NaBr = 3.40 g
Mass of solution = Mass of NaBr + Mass of H2O = 3.40 g + 17.4 g = 20.8 g
%NaBr = (Mass of NaBr / Mass of solution) × 100%
%NaBr = (3.40 g / 20.8 g) × 100% = 16.3%
%NaBr = 16.3%
Answer: The percentage by mass of sodium bromide in the solution is 16.3%
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