Answer to Question #335077 in Chemistry for 8lo

Question

Calculate the pressure, in atm, required to compress a sample of helium gas from 5.00 L

(at 1.00 atm) to 2.00 L.

Answer 1

P₁ = 1.00 atm

V₁ = 5.00 L

T₁ = T₂ = constant

P₂ = ???

V₂ = 2.00 L

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the pressure, solve the equation for P₂:

P₂ = P₁V₁ / V₂

P₂ = (1.00 atm × 5.00 L) / (2.00 L) = 2.50 atm

P₂ = 2.50 atm

Answer: 2.50 atm