Answer to Question #334169 in Chemistry for shimmy

Question

Solve: A certain light bulb containing argon has a pressure of 1.20 atm at 18°C. If it

will be heated to 85°C at constant volume, what will be the resulting pressure? Given: P₁ = 1.20 atm.                                                                             P₂ = ?

T₁ = 180C + 273.15= 291.15 K                            T₂ = 850C + 273.15=358.15 K

 

Answer 1

Given:

P₁ = 1.20 atm

T₁ = 18°C + 273.15 = 291.15 K

V₁ = V₂ = constant

P₂ = unknown

T₂ = 85°C + 273.15 = 358.15 K

Formula: P₁ / T₁ = P₂ / T₂

Solution:

Since the volume and amount of gas remain unchanged, Gay-Lussac's law can be used.

Gay-Lussac's law can be expressed as: P₁ / T₁ = P₂ / T₂

P₁T₂ = P₂T₁

To find the resulting pressure, solve the equation for P₂:

P₂ = P₁T₂ / T₁

P₂ = (1.20 atm × 358.15 K) / (291.15 K) = 1.476 atm = 1.48 atm

P₂ = 1.48 atm

Answer: The resulting pressure will be 1.48 atm