4.You have added 10 litres of air to a balloon at 1.0 atm. What is the new volume of the balloon if you take it to a 0.90 atmospheric pressure ?
P1 = 1.00 atm
V1 = 10 L
T1 = T2 = constant
P2 = 0.90 atm
V2 = ???
Solution:
Since the temperature and amount of gas remain unchanged, Boyle's law can be used.
Boyle's gas law can be expressed as: P1V1 = P2V2
To find the new voume of the balloon, solve the equation for V2:
V2 = P1V1 / P2
V2 = (1.00 atm × 10 L) / (0.90 atm) = 11.1 L
V2 = 11.1 L
Answer: The new volume of the balloon is 11.1 liters
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