Answer to Question #332355 in Chemistry for Sha

Question

Will AgIO3 precipitate when 20 mL of 0.010M AgIO3 is mixed with 10 mL of 0.015M NaIO3? Ksp of AgIO3 is 3.1× 10-8

Answer 1

Will AgIO₃ precipitate when 20 mL of 0.010 M AgNO₃ is mixed with 10 mL of 0.015 M NaIO₃?

K_sp of AgIO₃ is 3.1×10⁻⁸

Solution:

AgNO₃ → Ag⁺ + NO₃⁻

So, the molarity of Ag⁺ is same as the molarity of AgNO₃ (0.010 M)

NaIO₃ → Na⁺ + IO₃⁻

So, the molarity of IO₃⁻ is same as the molarity of NaIO₃ (0.015 M)

Moles of Ag⁺ = (0.010 M) × (20 mL) × (1L / 1000 mL) = 0.0002 mol

Moles of IO₃⁻ = (0.015 M) × (10 mL) × (1L / 1000 mL) = 0.00015 mol

Total volume = 20 mL + 10 mL = 30 mL = 0.03 L

Therefore,

[Ag⁺] = (0.0002 mol) / (0.03 L) = 0.00667 M

[IO₃⁻] = (0.00015 mol) / (0.03 L) = 0.0050 M

AgIO₃ → Ag⁺ + IO₃⁻

Q_sp = [Ag⁺] × [IO₃⁻] = (0.00667) × (0.0050) = 3.33×10⁻⁵

Since Q_sp > K_sp

3.33×10⁻⁵ > 3.1×10⁻⁸

Therefore,

AgIO₃ will precipitate

Answer: AgIO₃ will precipitate