Ammonia (NH3) combines with oxygen to give nitrogen monoxide and water. What amount (moles) of oxygen is required to use up 2.75 moles of ammonia?
ammonia = NH3
oxygen = O2
nitrogen monoxide = NO
water = H2O
Solution:
Balanced chemical equation:
4NH3 + 5O2 → 4NO + 6H2O
According to stoichiometry:
4 mol of NH3 react with 5 mol of O2
Thus, 2.75 mol of NH3 react with:
(2.75 mol NH3) × (5 mol O2 / 4 mol NH3) = 3.4375 mol O2 = 3.44 mol O2
Answer: 3.44 moles of oxygen (O2) is required
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