Answer to Question #328406 in Chemistry for virgy

Question

how many moles of cadmium chloride can be produced from 45,1 grams of cadmium with excess sulfur?

Answer 1

(1): How many moles of cadmium chloride can be produced from 45.1 grams of cadmium with excess chlorine gas?

Solution (1):

The molar mass of cadmium (Cd) is 112.411 g/mol

Therefore,

Moles of Cd = (45.1 g Cd) × (1 mol Cd / 112.411 g Cd) = 0.4012 mol Cd

Balanced chemical equation:

Cd + Cl₂ → CdCl₂

According to stoichiometry:

1 mol of Cd produces 1 mol of CdCl₂

Thus, 0.4012 mol of Cd produce:

(0.4012 mol Cd) × (1 mol CdCl₂ / 1 mol Cd) = 0.4012 mol CdCl₂

The molar mass of cadmium chloride (CdCl₂) is 183.32 g/mol

Therefore,

Mass of CdCl₂ = (0.4012 mol CdCl₂) × (183.32 g CdCl₂ / 1 mol CdCl₂) = 73.55 g CdCl₂

Mass of CdCl₂ = 73.55 g

Answer (1): 73.55 grams of cadmium chloride (CdCl₂) are produced

(2): How many moles of cadmium sulfide can be produced from 45.1 grams of cadmium with excess sulfur?

Solution (2):

The molar mass of cadmium (Cd) is 112.411 g/mol

Therefore,

Moles of Cd = (45.1 g Cd) × (1 mol Cd / 112.411 g Cd) = 0.4012 mol Cd

Balanced chemical equation:

Cd + S → CdS

According to stoichiometry:

1 mol of Cd produces 1 mol of CdS

Thus, 0.4012 mol of Cd produce:

(0.4012 mol Cd) × (1 mol CdS / 1 mol Cd) = 0.4012 mol CdS

The molar mass of cadmium sulfide (CdS) is 144.47 g/mol

Therefore,

Mass of CdS = (0.4012 mol CdS) × (144.47 g CdS / 1 mol CdS) = 57.96 g CdS

Mass of CdS = 57.96 g

Answer (2): 57.96 grams of cadmium sulfide (CdS) are produced