Question

how many grams of oxygen gas must be reacted with excess sulfur dioxide to produce 87,1 g of SO3?

Answer 1

2SO₂ + O₂ = 2SO₃

According to the equation, n (O₂) = 1/2 x n (SO₃)

n = m / M

M (SO₂) = 64.1 g/ mol

M (O₂) = 32 g/ mol

M (SO₃) = 80.1 g/ mol

n (SO₃) = m / M = 87.1 / 80.1 = 1.1 mol

n (O₂) = 1/2 x n (SO₃) = 1/2 x 1.1 = 0.54 mol

m (O₂) = n x M = 0.54 x 32 = 17.4 g