Question #32589

how do I prepare 0.5M hcl in 1l from conc hcl

Expert's answer

How do I prepare 0.5M hcl in 1l from conc hcl

Solution

The 1l conc HCl (36.5% of HCl) is 11.8M. (d=1.18 g/cm³; Mᵣ=36.5 g/mol)


C1V1=C2V2\mathrm{C_1V_1 = C_2V_2}


We want to prepare 1l 0.5M HCl => 0.5*1; and we have to take x l of 11.8M HCl.


x=0.5111.8=0.0424l.x = \frac{0.5*1}{11.8} = 0.0424 \, \mathrm{l}.


So you have to take 0.0424l of conc HCl and 0.9576l of water.


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