Answer to Question #324805 in Chemistry for Kai

Question

A box of miniature cars contains 5 red cars, 7 blue cars, and 6 black cars. Two cars are drawn, but the first car drawn is not replaced. What is the probability of getting a red car on the first draw and a blue car on the second draw?

Answer 1

1) P = (100 x 5) / (5+7+6) = 28%

2) P = (100 x 7) / (5+7+6) = 39%