Question

balance the following equation and detemine how many grams of fecl3 will be produced if you start with 3.44g of fe

Answer 1

Ferum reacts with chlorine gas to produce ferum(III)chloride. Reaction for this process is next :

$$2 \mathrm{Fe} + 3 \mathrm{Cl_2} \rightarrow 2 \mathrm{FeCl_3}$$

It is possible to find mass of $\mathrm{FeCl_3}$ by using this equation.

3.44

m

$$2 \mathrm{Fe} + 3 \mathrm{Cl_2} \rightarrow 2 \mathrm{FeCl_3}$$

Mw of Fe Mw of $\mathrm{FeCl_3}$

Mw of $\mathrm{Fe} = 56$

Mw of $\mathrm{FeCl_3} = 162$, so

3.44

m

$$2 \mathrm{Fe} + 3 \mathrm{Cl_2} \rightarrow 2 \mathrm{FeCl_3}$$

56 162

$$\mathrm{m} = 3.44 * 162 / 56 = 9.95\mathrm{g}$$