Question

using equation, show the formation of hydroxonium ions in an aqueous solution of tetraoxosulphate (iv) acid

Answer 1

using equation, show the formation of hydroxonium ions in an aqueous solution of tetraoxosulphate (iv) acid

Solution:

$$\mathrm{H_2SO_4} + \mathrm{H_2O} \rightarrow \mathrm{H_3O^+} + \mathrm{HSO_4^-}$$ $$\mathrm{HSO_4^-} + \mathrm{H_2O} \rightarrow \mathrm{H_3O^+} + \mathrm{SO_4^{2-}}$$

Tetraoxosulphate (vi) acid, being dissolved in water dissociates with formation of hydroxonium ions $\mathrm{H_3O^+}$. By the way, you have a mistake in description of the problem: tetraoxosulphate (iv) acid is nonexistent compound, tetraoxosulphate (vi) acid is correct way of writing.