Calculate K for the reaction :
2A + B <----> C + D
If at equilibrium, A = 0.4 mols/liter, mols/liter, B = 0.5 mols per liter. C = 0.3 mols per liter, and D = 0.8 mols per liter.
Solution:
The chemical reaction:
2A + B ⇌ C + D
The equilibrium constant expression for the reaction system:
[A] = 0.4 mol/L
[B] = 0.5 mol/L
[C] = 0.3 mol/L
[D] = 0.8 mol/L
Therefore,
K = (0.3 × 0.8) / (0.5 × 0.42) = (0.24) / (0.08) = 3.0
K = 3.0 L/mol
Answer: The equilibrium constant (K) for the reaction is 3.0 liter/mol
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