Answer to Question #313101 in Chemistry for Delle

Question

a.      Cisplatin or Platinol has a chemical PtCl2(NH3)2 that is used in the treatment of certain cancers. Calculate (a) the amount (mol) of compound in 285.3 g of cisplatin; (b) the number of hydrogen atoms in 0.98 mol of cisplatin.

Answer 1

Solution:

(a):

The molar mass of cisplatin (PtCl₂(NH₃)₂) is 300.051 g/mol

Mass of PtCl₂(NH₃)₂ is 285.3 g

Therefore,

Moles of cisplatin = (285.3 g) × (1 mol / 300.051 g) = 0.9508 mol

The moles of cisplatin is 0.9508 mol

(b):

PtCl₂(NH₃)₂ ⟶ 6H

According to stoichiometry:

1 mol of cisplatin contains 6 mol of H atoms

Thus, 0.98 mol of cisplatin contains (0.98×6) = 5.88 mol of H atoms

One mole of any substance contains 6.022×10²³ particles

Therefore,

Number of H atoms = (5.88 mol) × (6.022×10²³ atoms / 1 mol) = 3.54×10²⁴ atoms

3.54×10²⁴ hydrogen atoms in 0.98 mol of cisplatin