2. What is the concentration of an HNO3 solution if 25.0 ml reacts with 38.5 ml of 0.145 M K2PO4?
Solution:
Balanced chemical equation:
3HNO3 + K3PO4 → 3KNO3 + H3PO4
According to stoichiometry:
Moles of HNO3 / 3 = Moles of K3PO4
or:
Molarity of HNO3 × Volume of HNO3 = 3 × Molarity of K3PO4 × Volume of K3PO4
Therefore,
Molarity of HNO3 = 3 × Molarity of K3PO4 × Volume of K3PO4 / Volume of HNO3
Molarity of HNO3 = (3 × 0.145 M × 38.5 mL) / (25.0 mL) = 0.6699 M ≈ 0.670 M
Molarity of HNO3 = 0.670 M
Answer: The concentration of an HNO3 solution is 0.670 M
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