Question #31149

if 0.5M h2so4 contains 50mL then 1M h2so4 contains how much mL?

Expert's answer

Task:

if 0.5M h2so4 contains 50mL then 1M h2so4 contains how much mL?

Solution:

The number of moles of H2SO4\mathrm{H}_2\mathrm{SO}_4 doesn't change in both cases.


n(mol)=C(M)V(L)n(\mathrm{mol}) = C(M) \cdot V(L)


According to the equation n1=n2n_1 = n_2, we can write the following:


C1(M)V1(L)=C2(M)V2(L)C_1(M) \cdot V_1(L) = C_2(M) \cdot V_2(L)


The volume of 1M solution is


V1(L)=C2(M)V2(L)/C1(M)V_1(L) = C_2(M) \cdot V_2(L) / C_1(M)V1(mL)=0.550/1=25 mLV_1(mL) = 0.5 \cdot 50 / 1 = 25 \text{ mL}


Answer: V1(mL)=25 mLV_1(mL) = 25 \text{ mL}

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