What is the (a) H+ ion concentration, (b) pH, (c) OH- ion concentration and (d) pOH of a 0.001 M solution of NaOH?
NaOH is a strong base because NaOH completely dissociates into sodium (Na+) and hydroxide (OH−) ions in aqueous solutions.
Equation representing the dissociation of NaOH:
NaOH(aq) → Na+(aq) + OH−(aq)
The molarity of NaOH is 0.001 M
CM(NaOH) = [OH−] = [Na+] = 0.001 M
Thus,
[OH−] = 0.001 M
pOH = −log[OH−] = −log[0.001] = 3
pH = 14 − pOH = 14 − 3 = 11
[H+] = 10−pH = 10−11 = 1.0×10−11 M
Answer:
(a): [H+] = 1.0×10−11 M
(b): pH = 11
(c): [OH−] = 0.001 M
(d): pOH = 3
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