Answer to Question #309581 in Chemistry for mikmik

Question

if a 0.22560g of sodium bicarbonate is titrated with 0.1165N sulphuric acid. what volume of acid is required to reach the end point?

Answer 1

Solution:

sodium bicarbonate = NaHCO₃

sulphuric acid = H₂SO₄

Calculate the moles of sodium bicarbonate (NaHCO₃):

The molar mass of NaHCO₃ is 84.007 g/mol

Therefore,

(0.22560 g NaHCO₃) × (1 mol NaHCO₃ / 84.007 g NaHCO₃) = 0.0026855 mol NaHCO₃

Balanced chemical equation:

2NaHCO₃ + H₂SO₄ → Na₂SO₄ + 2H₂O + 2CO₂

According to stoichiometry:

Moles of NaHCO₃ = 2 × Moles of H₂SO₄

OR:

Moles of NaHCO₃ = Normality of H₂SO₄ × Volume of H₂SO₄

Therefore,

Volume of H₂SO₄ = Moles of NaHCO₃ / Normality of H₂SO₄

Volume of H₂SO₄ = (0.0026855 mol) / (0.1165 N) = 0.02305 L = 23.05 mL

Volume of H₂SO₄ = 23.05 mL

Answer: 23.05 mL of H₂SO₄ is required to reach the end point