Answer to Question #307696 in Chemistry for ayden

Question

Maintaining constant pressure, the volume of a gas is increased from 18.0 L to 32.0 L by heating it. If the original temperature was 18.0°C, what is the new temperature in degrees Kelvin? Reminder, convert your temperature to Kelvin before you begin the problem.

Answer 1

P₁ = P₂ = constant

V₁ = 18.0 L

T₁ = 18.0°C + 273.15 = 291.15 K

V₂ = 32.0 L

T₂ = unknown

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the final temperature, solve the equation for T₂:

T₂ = V₂T₁ / V₁

T₂ = (32.0 L × 291.15 K) / (18.0 L) = 517.6 K

T₂ = 517.6 K

Answer: The new temperature is 517.6 K